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Arcs Chords And Central Angles

6.12: Chords and Fundamental Angle Arcs

  • Page ID
    5027
  • Arcs adamant by angles whose vertex is the centre of a circle and chords (segments that connect two points on a circumvolve).

    Chords in Circles

    Chord Theorems

    At that place are several important theorems virtually chords that volition aid you lot to analyze circles better.

    1. Chord Theorem #1: In the same circle or congruent circles, minor arcs are congruent if and merely if their respective chords are congruent.

    f-d_2ea1cf98cd7bab0d6cd479df866ce1d1371c7edd47866c18a95bbfd3+IMAGE_TINY+IMAGE_TINY.png
    Effigy \(\PageIndex{1}\)

    In both of these pictures, \(\overline{Exist}\cong \overline{CD}\) and \(\widehat{Be}\cong \widehat{CD}\).

    2. Chord Theorem #2: The perpendicular bisector of a chord is also a diameter.

    f-d_19e5e04c404c16527fd5c5d56ead6a6d4920136a9b025b6e667e4445+IMAGE_TINY+IMAGE_TINY.png
    Figure \(\PageIndex{2}\)

    If \(\overline{AD}\perp \overline{BC}\) and \(\overline{BD}\cong \overline{DC}\) so \(\overline{EF}\) is a diameter.

    3. Chord Theorem #three: If a diameter is perpendicular to a chord, then the diameter bisects the chord and its corresponding arc.

    f-d_19e5e04c404c16527fd5c5d56ead6a6d4920136a9b025b6e667e4445+IMAGE_TINY+IMAGE_TINY.png
    Figure \(\PageIndex{three}\)

    If \(\overline{EF}\perp \overline{BC}\), then \(\overline{BD}\cong \overline{DC}\)

    4. Chord Theorem #4: In the aforementioned circumvolve or congruent circles, 2 chords are congruent if and simply if they are equidistant from the heart.

    f-d_99e22c456e3f4815417f855a0311378b46e0787fd21b0120f5151699+IMAGE_TINY+IMAGE_TINY.png
    Figure \(\PageIndex{4}\)

    The shortest distance from any point to a line is the perpendicular line between them. If \(Atomic number 26=EG\) and \(\overline{EF}\perp \overline{EG}\), and then \(\overline{AB}\) and \(\overline{CD}\) are equidistant to the center and\(\overline{AB}\cong \overline{CD}\).

    What if yous were given a circumvolve with 2 chords drawn through information technology? How could you make up one's mind if these ii chords were congruent?

    Example \(\PageIndex{ane}\)

    Find the value of \(x\) and \(y\).

    f-d_a040b0389542bb379fa6c030342257c30c5de4c41e22004f5236607e+IMAGE_TINY+IMAGE_TINY.png
    Figure \(\PageIndex{v}\)

    Solution

    The bore is perpendicular to the chord, which ways it bisects the chord and the arc. Set upwards equations for \(ten\) and \(y\).

    \(\begin{assortment}{rlr}
    (three x-four)^{\circ} & =(5 ten-18)^{\circ} & y+four=2 y+i \\
    xiv & =2 x & 3=y \\
    7 & =x
    \stop{array}\)

    Instance \(\PageIndex{2}\)

    \(BD=12\) and \(AC=three\) in \(\bigodot A\). Notice the radius.

    f-d_e0b218827409e0747e0c8ecebad5c4eab55aa4db23adff4bc47203d4+IMAGE_TINY+IMAGE_TINY.png
    Effigy \(\PageIndex{6}\)

    Solution

    Start find the radius. \(\overline{AB}\) is a radius, and then nosotros can use the right triangle \Delta ABC\) with hypotenuse \(\overline{AB}\). From Chord Theorem #3, \(BC=six\).

    \(\begin{aligned} iii^2+6^2&=AB^two \\ ix+36&=AB^2 \\ AB&=\sqrt{45}=3\sqrt{v}\end{aligned}\)

    Instance \(\PageIndex{iii}\)

    Use \(\bigodot A\) to respond the following.

    f-d_ca0baf3d34c480e5bd5781f6dd90473b3da0b492c4bbfe46186ef20e+IMAGE_TINY+IMAGE_TINY.png
    Figure \(\PageIndex{7}\)
    1. If \(k\widehat{BD}=125^{\circ}\), find \(k\widehat{CD}\).
    2. If \(m\widehat{BC}=80^{\circ}\), notice \(chiliad\widehat{CD}\).

    Solution

    1. \(BD=CD\), which means the arcs are congruent too. \(m\widehat{CD}=125^{\circ}\).
    2. \(k\widehat{CD}\cong m\widehat{BD}\) considering \(BD=CD\).

    \(\begin{aligned} m\widehat{BC}+thousand\widehat{CD}+k\widehat{BD}&=360^{\circ} \\ 80^{\circ}+2m\widehat{CD}&=360^{\circ} \\ 2m\widehat{CD}&=280^{\circ} \\ thousand\widehat{CD}=140^{\circ}\end{aligned}\)

    Example \(\PageIndex{4}\)

    Detect the values of \(x\) and \(y\).

    f-d_5322912138f6a893d14b0f2210f643adc820904ff5e0813b4e9f0de8+IMAGE_TINY+IMAGE_TINY.png
    Figure \(\PageIndex{eight}\)

    Solution

    The diameter is perpendicular to the chord. From Chord Theorem #iii, \(x=6\) and \(y=75^{\circ}\).

    Example \(\PageIndex{5}\)

    Observe the value of \(x\).

    f-d_4c6c48ef93ea52ed1fe355459e5aaaf3616653d3ee5a6959905a9efc+IMAGE_TINY+IMAGE_TINY.png
    Effigy \(\PageIndex{9}\)

    Solution

    Considering the distance from the centre to the chords is equal, the chords are congruent.

    \(\begin{aligned} 6x−7&=35 \\ 6x&=42 \\ x&=seven \cease{aligned}\)

    Review (Answers)

    To meet the Review answers, open this PDF file and look for section 9.4.

    Vocabulary

    Term Definition
    chord A line segment whose endpoints are on a circumvolve.
    circle The set of all points that are the same distance away from a specific point, called the center .
    diameter A chord that passes through the center of the circle. The length of a diameter is two times the length of a radius.
    radius The distance from the eye to the outer rim of a circle.

    Additional Resources

    Video: Chords in Circles Principles - Basic

    Activities: Chords in Circles Discussion Questions

    Study Aids: Circles: Segments and Lengths Study Guide

    Do: Chords and Central Angle Arcs

    Arcs Chords And Central Angles,

    Source: https://k12.libretexts.org/Bookshelves/Mathematics/Geometry/06%3A_Circles/6.12%3A_Chords_and_Central_Angle_Arcs

    Posted by: farrellalks1964.blogspot.com

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